9x^2+17x+8=3x^2

Solution for 9x^2+17x+8=3x^2 equation:

9x^2+17x+8=3x^2

We move all terms to the left:

9x^2+17x+8-(3x^2)=0

determiningTheFunctionDomain
9x^2-3x^2+17x+8=0

We add all the numbers together, and all the variables

6x^2+17x+8=0

a = 6; b = 17; c = +8;
Δ = b2-4ac
Δ = 172-4·6·8
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{97}}{2*6}=\frac{-17-\sqrt{97}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{97}}{2*6}=\frac{-17+\sqrt{97}}{12}
$